Help me please !!!!!!!!!
1 answer:
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Change the function into vertex form:
f(x)=x²-10x+16
make a square by (adding half of -10)², which is 25, then subtract it:
f(x)=x²-10x+25-25+16
f(x)=(x-5)²-9
so the vertex is at (5,-9)
another way to do it:
f(x)=x²-10x+16
the vertex is when x=-
, b=-10, a=1 in this case.
x=-(-10/2*1)=5
plug x=5 into the quadratic function, you get f(x)=-9
f(x)=x²-10x+16
make a square by (adding half of -10)², which is 25, then subtract it:
f(x)=x²-10x+25-25+16
f(x)=(x-5)²-9
so the vertex is at (5,-9)
another way to do it:
f(x)=x²-10x+16
the vertex is when x=-
x=-(-10/2*1)=5
plug x=5 into the quadratic function, you get f(x)=-9
Answer:
probability that Shaun loses both games
Step-by-step explanation:
Games are independent, so we find each separate probability, and multiply them.
In a chess club the probability that Shaun will beat Mike is 3/8.
So probability that Shaun loses.
The probability that Shaun will beat Tim is 5/7 .
So probability that Shaun loses.
What is the probability that Shaun loses both games?
This is:
probability that Shaun loses both games