Answer:
D. (1/4, -2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -8x
4x - y = 3
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 4x - (-8x) = 3
- Simplify: 4x + 8x = 3
- Combine like terms: 12x = 3
- Isolate <em>x</em>: x = 3/12
- Simplify: x = 1/4
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: y = -8x
- Substitute in <em>x</em>: y = -8(1/4)
- Multiply: y = -2
Answer:
The correct option is;
Use a scale factor of 2
Step-by-step explanation:
The parameters given are;
A = (1, -6)
B = (5, -6)
C = (6, -2)
D = (0, -2)
A'' = (1.5, 4)
B'' = (3.5, 4)
C'' = (4, 2)
D'' = ( 1, 2)
We note that the length of side AB in polygon ABCD = √((5 -1)² + (-6 - (-6))²) = 4
The length of side A''B'' in polygon A''B''C''D'' = √((3.5 -1.5)² + (4 - 4)²) = 2
Which gives;
AB/A''B'' = 4/2 = 2
Similarly;
The length of side BC in polygon ABCD = √((6 -5)² + (-2 - (-6))²) = √17
The length of side B''C'' in polygon A''B''C''D'' = √((4 -3.5)² + (2 - 4)²) = (√17)/2
Also we have;
The length of side CD in polygon ABCD = √((6 -0)² + (-2 - (-2))²) = 6
The length of side C''D'' in polygon A''B''C''D'' = √((4 -1)² + (2 - 2)²) = 3
For the side DA and D''A'', we have;
The length of side DA in polygon ABCD = √((1 -0)² + (-6 - (-2))²) = √17
The length of side D''A'' in polygon A''B''C''D'' = √((1.5 -1)² + (4 - 2)²) = (√17)/2
Therefore the Polygon A B C D can be obtained from polygon A''B''C''D'' by multiplying each side of polygon A''B''C''D'' by 2
The correct option is therefore;
Use a scale factor of 2.
Step-by-step explanation:
f(2)= -2×2×2+ 6×2 -7
=-8+12-7
=-3
Ratio is the comparison of sizes of two quantities of the same unit. Proportions are the equality of two ratios. A/b =c/d
Answer:
Therefore, we conclute that Kate run 1 mile and 7/15 of a mile for the week.
Step-by-step explanation:
We know that Kate runs 2/3 of a mile on Mondays, Wednesdays and Thursdays. She runs 4/5 of a mile on Tuesday and Fridays. We calculate how many miles does Kate run during the week.
Therefore, we get
Therefore, we conclute that Kate run 1 mile and 7/15 of a mile for the week.
