A=P+PRT solve for the indicated variable R

Mathematics

2 answers:

Arisa [49]3 years ago

7 0

Answer:

(A-P)/PT = R

Step-by-step explanation:

A=P+PRT

Subtract P from each side

A-P=P-P+PRT

A- P = PRT

Divide each side by PT

(A-P)/PT = PRT/PT

(A-P)/PT = R

sergey [27]3 years ago

6 0

Answer:

R=A/PT-P/T

Step-by-step explanation:

A=P+PRT

-P -P

_______

A-P=PRT

÷PT ÷PT

_______

A/PT-P/T=R

You might be interested in

Which graph best represents the relationship between time and the number of teams registered?

alexdok [17]

<h2>Explanation:</h2><h2></h2>

The complete question is in the attached file. So we have to choose between two graphs. On of them is a linear model while the other is an exponential model. From the statements, we have a relationship between time and the number of teams registered. So we can establishes variables in the following form:

$x:\text{Time} \\ \\ y:\text{Number of teams registered}$

We also know that each week 6 teams register to participate, so:

$\bullet \ \text{For week 0:} \rightarrow \text{0 teams registered} \\ \\ \bullet \ \text{For week 1:} \rightarrow \text{6 teams registered} \\ \\ \bullet \ \text{For week 2:} \rightarrow \text{12 teams registered (Because 6+12)} \\ \\ \bullet \ \text{For week 3:} \rightarrow \text{18 teams registered (Because 12+6)}$

As you can see, as x increases one week, y increases at a constant ratio of 6. Therefore, this can be modeled by a linear function given by the form:

$y=6x$

In conclusion, <em>the linear model (first graph below) is the one that bests represents the relationship between time and the number of teams registered.</em>