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4 years ago

Consider the given function and the given interval.

Mathematics

1 answer:

docker41 [41]4 years ago

7 0

Answer:

(a) fave = 8

(b) c = 64/9

Step-by-step explanation:

(a) The average value of the function is its integral over the interval, divided by the width of the interval.

$f_{ave}=\displaystyle\frac{1}{16-0}\int_0^{16} {3x^{\frac{1}{2}}} \, dx=\left.\frac{x^{3/2}}{8}\right|_0^{16}=8$

(b) We want ...

f(c) = 8

3√c = 8 . . . . . use f(c)

√c = 8/3 . . . . . divide by 3

c = (8/3)² . . . . square

c = 64/9

(c) c ≈ 7.111

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What words can you use to read 14.895

Setler79 [48]

Hey there!

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3 years ago

Read 2 more answers

Simplify.<br> -3(u + 3) + 4(4u + 2)

sergeinik [125]

Hello!

So, here you want to do the distributive property.

Start on the left side of the + sign...

-3*u = -3u

-3*3 = -9

So we now we have:

(-3u + -9) + 4(4u + 2)

Now we focus on the right side of the + sign...

4*4u=16u

4*2=8

So now we have:

(-3u + -9) + (16u + 8)

Now you want to combine like terms. Start by adding terms with the same variable. So, we need to add -3u and 16u

<em>-3u + 16u =</em> 13u

Now we have:

13u + -9 + 8

Now add the constants, -9 + 8

-9 + 8 = -1

So, the simplified expression would be:

13u - 1 or 13u + -1

6 0

3 years ago

Read 2 more answers

Based on the results from part C, which two statements correctly interpret actions the business should take?

icang [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

Can someone help me #11 PLEASE SHOW YOUR WORK

damaskus [11]

Since the triangle is equilateral, QR = RS = QS.
a. MS = (1/2)74
MS = 37
b. Half of the equilateral triangle makes a right triangle. Use Pythagorean Theorem to find QM.
a^2 + b^2 = c^2
37^2 + b^2 = 74^2
1369 + b^2 = 5476
subtract 1369 from both sides
b^2 = 4107
take the square root if both sides
b = 64.1
QM = 64.1

5 0

4 years ago

He list shows the growth in centimeters of 12 plants during one week. 6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14 Which box plot best

kumpel [21]

Answer:

Step-by-step explanation:

Hello!

You have the growth of 12 plants over a week (cm)

To construct a box plot you have to identify the 1st, 2nd, and 3rd Quartiles for the box and the maximum and minimum values for the whiskers.

Box

1st Quartile (Q₁)

Is the value of the data set that separates the bottom 25% from the top 75%. First, you need to calculate its position:

PosQ₁= n/4= 12/4= 3

So the first quartile is the third value.

6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14

Q₁= 7

2nd Quartile/ Median (Q₂/Me)

PosMe= 12/2= 6

The second quartile in the 6th value.

6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14

Q₂=Me= 8

3rd Quartile (Q₃)

PosQ₃= n*(3/4)= 12*(3/4)= 9

The third quartile is the 9th value.

6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14

Q₃= 10

The left whisker extends from the Q₁ to the minimum value.

The right whisker extends from the Q₃ to the maximum value.

Min= 6

Max= 14

'------| | |-------'

6 7 8 10 14

The box plot that best displays a summary of the data, is C.

I hope this helps!

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4 years ago