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3 years ago

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A quarter back is sacked for loss of 5 yards. Then the team gains 12 yards. What integer can be used to explain the net gain or

loss of the three plays?

1 answer:

bonufazy [111]3 years ago

7 0

The integer is obviously 12

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What is the answer????

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Measure of angle 1 is 117°
measure of angle 2 is 72°

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3 years ago

3≤7+g<br> Another solution one :)<br><br> What is the solution?

gizmo_the_mogwai [7]

Answer:

Inequality Form:

g ≥ − 4

Interval Notation:

[ − 4 , ∞ )

Step-by-step explanation:

Solve for g by simplifying both sides of the inequality, then isolating the variable.

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3 years ago

A rectangular prism has a length of 4 cm a width of 6 cm and a height of 3 cm what is it’s volume

liraira [26]

Answer: 72

Step-by-step explanation:

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3 years ago

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If the area of the larger circle is 25 times the area of the smaller circle, then the radius of the larger circle is how many ti

IrinaVladis [17]

Answer:

easy peasy (again)

Step-by-step explanation:

given is that, area of the larger one is 25 times more than the smaller one

so, just put it in the area formula,

let the radius of the larger circle be represented by = R

and of the smaller circle be = r

then, (pi) (R)^2 =25 x (pi) (r)^2

=> dividing the equation by pi on both sides, also taking square root on both sides

=> R = 25 r

that would be the radius of the larger circle is 25 times bigger than the smaller radius

(all u need is to pay attention to the data given in the question and the relation between all that data itself) then it'll look like magic of how the question gets solved...the answer is always in front of you, only thing is to look harder ...good luck with what you are aiming to achieve

3 0

3 years ago

Which function is the same as y = 3 cosine (2 (x startfraction pi over 2 endfraction)) minus 2? y = 3 sine (2 (x startfraction p

kirza4 [7]

The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

$\sin(\theta) = \cos(\pi/2 - \theta)\\\sin(\theta + \pi/2) = -\cos(\theta)\\\cos(\theta + \pi/2) = \sin(\theta)$

to convert the sine to cosine.

<h3>Which trigonometric functions are positive in which quadrant?</h3>

In first quadrant (0 < θ < π/2), all six trigonometric functions are positive.
In second quadrant(π/2 < θ < π), only sin and cosec are positive.
In the third quadrant (π < θ < 3π/2), only tangent and cotangent are positive.
In fourth (3π/2 < θ < 2π = 0), only cos and sec are positive.

(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

$y= 3\cos(2(x + \pi/2)) - 2$

The options are:

$y= 3\sin(2(x + \pi/4)) - 2$
$y= -3\sin(2(x + \pi/4)) - 2$
$y= 3\cos(2(x + \pi/4)) - 2$
$y= -3\cos(2(x + \pi/2)) - 2$

Checking all the options one by one:

Option 1: $y= 3\sin(2(x + \pi/4)) - 2$

$y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2$

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

Option 2: $y= -3\sin(2(x + \pi/4)) - 2$

This option if would be true, then from option 1 and this option, we'd get:
$-3\sin(2(x + \pi/4)) - 2= -3\sin(2(x + \pi/4)) - 2\\2(3\sin(2(x + \pi/4))) = 0\\\sin(2(x + \pi/4) = 0$

which isn't true for all values of x.

Thus, this option is not same as the given function.

Option 3: $y= 3\cos(2(x + \pi/4)) - 2$

The given function is $y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2$

This option's function simplifies as:

$y= 3\cos(2(x + \pi/4)) - 2 = 3\cos(2x + \pi/2) -2 = -3\sin(2x) - 2$

Thus, this option isn't true since $\sin(2x) \neq \cos(2x)$ always (they are equal for some values of x but not for all).

Option 4: $y= -3\cos(2(x + \pi/2)) - 2$

The given function simplifies to: $y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2$

The given option simplifies to:

$y= -3\cos(2(x + \pi/2)) - 2 = -3\cos(2x + \pi ) -2\\y = 3\cos(2x) -2$

Thus, this function is not same as the given function.

Thus, the function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

Learn more about sine to cosine conversion here:

brainly.com/question/1421592

4 0

2 years ago

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