Answer:
The given quadrilateral is a parallelogram.
Step-by-step explanation:
If a quadrilateral is a parallelogram , then the opposite sides would be equal.
Here we are going to equate the length of 1 pair of opposite sides to find the value of x and use this value of x to verify whether the other pair of opposite sides are equal.
AB = 6x
BC = 3x
DC = x + 15
AD = 9
Equate AB and CD,
6x = x + 15
5x = 15
x = 3
Now BC and DA should be equal.
BC = 3x = 9
Also DA = 9
As we can see, the other pair of opposite sides are also equal.
Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent.
Hence , the given quadrilateral is a parallelogram.
Let's use the variable E to represent the total value spent by Elena and T to represent the total value spent by Taniy.
If Elena spent $7.45 plus the cost of 3 pounds of cherries, the expression for the amount she spent is:
Taniy spent $3.35 plus the cost of 2 pounds of cherries, so the expression for the amount the spent is:
To find how much more Elena spent, let's subtract both expressions:
Therefore the answer is 4.1 + p.
Answer: The answer is 8.
Step-by-step explanation: The first step is to convert the expression into figures. We shall call the unknown number Y. So if we are told “the square of a number,” that means Y squared, or better still, Y^2. Further we are told “the difference between the square of a number and 40” and that can be written as;
Y^2 - 40.
Next we are told that this expression is equal to 3 times that number (that is 3Y). That can now be written out as follows,
Y^2 - 40 = 3Y
If we move all expressions to one side of the equation, what we would have is,
Y^2 - 3Y -40 = 0
(Remember that when a positive value crosses to the other side of an equation it becomes negative and vice versa)
We now have a quadratic equation
Y^2 -3Y - 40 = 0
By factorizing we now have
(Y -8) (Y + 5) = 0
Therefore Y - 8 = 0 or
Y + 5 = 0
Hence, Y = 8 or Y = -5
Since we are asked to calculate the positive solution, Y = 8
Si bo^se ko ne to ne co ne sa si
huma cona heto sho
(-2,6) (5,-8)
slope = (y2 - y1) / (x2 - x1)
slope = (-8 - 6) / (5 - (-2) = -14/7 = -2 <==
midpoint = (x1 + x2)/2 , (y1 + y2)/2
m = (-2 + 5)/2 , (6 - 8)/2
m = (3/2, -1) <===
distance = sqrt ((x2 - x1)^2 + (y2 - y1)^2)
d = sqrt ((5 - (-2)^2 + (-8 - 6)^2)
d = sqrt ((5 + 2)^2 + (-14^2))
d = sqrt (7^2 + 14^2)
d = sqrt (49 + 196)
d = sqrt 245
d = 15.65 <==
