If x2 + xy + y3 = 1, find the value of y''' at the point where x = 1.
1 answer:
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Answer:
The selling price is $79.53 .
Step-by-step explanation:
Formula
Let us assume that the cost price be x .
As given
Judy Garland Electronics operate on a net-profile rate of 20% on its printer cables.
If the markup is $8.95 and the overhead is $4.31 .
Selling price = Cost price + Markup price + Overhead price
Putting all the values in the above
= x + 8.95 + 4.31
= x + 13.26
Profit = Selling price - Cost price
= x + 13.26 - x
= 13.26
Putting all the values in the above
x = $ 66.3
Thus
Selling price = x + 13.26
= 66.3 + 13.26
= $ 79.53
Therefore the selling price is $79.53 .
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.
