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3 years ago

If x2 + xy + y3 = 1, find the value of y''' at the point where x = 1.

1 answer:

7 0

The value of y at the point where x is one is 0

because when you substitute x with 1, you are leaved with 1 + 1y + y^3 = 1

Then you do some math stuff and...

BAM! y = 0

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A) 0,2 x 5/7 + 11/14 = ?

NemiM [27]

I hope this helps you

6 0

3 years ago

Read 2 more answers

1.A cube has side lengths of 15 inches, what is the surface area and volume of the cube? 2. A cube has side lengths of 8 inches,

omeli [17]

Answer:

Cube 1: 3375 cubed inches, 1350 inches squared.

Cube 2: 512 cubed inches, 384 inches squared.

Step-by-step explanation:

Formula for Volume of a Cube: $V=s^3\\$ (s - side length)

Formula for Surface Area of a Cube: $SA=6s^2$ (s- side length)

The side length's 15 inches.

Find the volume:

$V=15^3\\\rightarrow 15*15*15=3375\\\boxed {V=3375}$

The volume of cube one is 3375in³.

Find the surface area:

$SA=6(15)^2\\\rightarrow 15^2 = 225\\SA = 6 * 225\\\boxed {SA=1350}$

The surface area of cube 1 is 1350in².

The side length's 8 inches.

Find the volume:

$V=8^3\\\rightarrow 8*8*8= 512\\\boxed {V=512}$

The volume of cube two is 512in³.

Find the surface area:

$SA=6(8)^2\\\rightarrow 8^2=64\\SA=6*64\\\boxed {SA=384}$

The surface area of cube 2 is 384in².

<em>Brainilest Appreciated. </em>

3 0

3 years ago

What is 6y−12=−3x in standard form?

aalyn [17]

3x + 6y = 12.
In standard form.

5 0

3 years ago

Ben wrestles in the 132 to 138- pound weight class. If he currently weighs 133 pounds, how much can he gain if he wishes to stay

zzz [600]

Answer:

2 to 8 pounds his can gain.

Step-by-step explanation:

3 0

3 years ago

Find 2 numbers who product is 15 and sum is 16.

Marizza181 [45]

Answer:

15 and 1

Step-by-step explanation:

x and y are two numbers.

Two equations:

x · y = 15

x + y = 16

Rearrange one of the equations (I'll rearrange the sum equation):

x + y = 16

x = 16 - y

Substitute that to the other equation and solve for y:

x · y = 15

(16 - y) · y = 15

16 - y · y = 15

16 - y² = 15

-y² = 15 - 16

-y² = -1

y² = 1

y = √1

y = 1

Now substitute that to any of the equation and solve for x (in here, I'll choose the multiplication one):

x · y = 15

x · 1 = 15

x = 15

Now verify:

15 · 1 = 15

15 + 1 = 16

This is correct

6 0

3 years ago