Julie weighs 35 lbs, Ted weighs 70 lbs, and Mike weighs 105 lbs
Julie's weight = x
Ted's weight = 2x
Mike's weight = 3x
3x + 2x + x = 6x
6x = 210
x = 35
3(35) + 2(35) + 1(35) = 210
105 + 70 + 35 = 210
Let Edy's money be x.
Lucy: 35% more --- (135/100) x
x + (135/100) x = 206.80
(47/20)x = 206.80
47x = 206.8 x 20
47x =4136
x = 88
Edy saved $88.
Lucy saved (135/100)(88) = $118.80
6 because 14 divided by 2 is 7 and hassan would be the 7th one.
Check the picture below.
this is a case of the ambiguous case with an SSA, AC and CB are the sides and the angle is at A.
the ambiguous case has two triangles, the case when B is acute, CB sticks out, and the case when B is obtuse, CB sticks inside, it just so happen that those two angles for B are "supplementary" angles.
if you check the sin⁻¹ of that, we'll get the acute version of B, that's because of the constraints on the range of the inverse sine function, and we get ∡B ≈ 36.86989765°.
and of course, the other angle for B will be 180 - 36.86989765.