All categories

4 years ago

Work please and points for this

Mathematics

1 answer:

sergiy2304 [10]4 years ago

8 0

11×12=132
25-11=14
14/2=7, which is the bottom length of the triangles
A triangle plus a similar triangle=a square, so you would do length×height to solve it
7×12=84
84+132=216
The area is 216 ft

You might be interested in

2.907*10^3 write in standard form

Alika [10]

Answer:

2907

Step-by-step explanation:

3 0

3 years ago

The heights of 40 randomly chosen men are measured and found to follow a normal distribution. An average height of 175 cm is obt

AVprozaik [17]

Answer:

95% two-sided confidence interval for the true mean heights of men is [168.8 cm , 181.2 cm].

Step-by-step explanation:

We are given that the heights of 40 randomly chosen men are measured and found to follow a normal distribution.

An average height of 175 cm is obtained. The standard deviation of men's heights is 20 cm.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average height = 175 cm

$\sigma$ = population standard deviation = 20 cm

n = sample of men = 40

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ]

= [ $175-1.96 \times }{\frac{20}{\sqrt{40} } }$ , $175+1.96 \times }{\frac{20}{\sqrt{40} } }$ ]

= [168.8 cm , 181.2 cm]

Therefore, 95% confidence interval for the true mean height of men is [168.8 cm , 181.2 cm].

The interpretation of the above interval is that we are 95% confident that the true mean height of men will be between 168.8 cm and 181.2 cm.

3 0

3 years ago

Find the commission.

alexandr1967 [171]

The Commission is $21

4 0

4 years ago

im really sorry for asking so many questions its just my only way of getting these assignments done on time plus their due tomor

Paul [167]

Answer: 3.84 m

Step-by-step explanation: The biggest clue here is that the scale factor is 1:12.

1:12=32: $x$

To find $x$ , multiply 32 by 12. 32x12 is 384. You can't say the answer is 384, however, since the label for the actual water tower says "m" for meters instead of "cm" like for the model. 384 cm is equal to 3.84 m.

Hope this helped! ;)

4 0

3 years ago

Read 2 more answers

In order for the parallelogram to be a square, x = [ ? ].

insens350 [35]

Answer: x=6

Step-by-step explanation:

6 0

3 years ago