when it comes to checking if a function is even or odd, it boils down to changing the argument, namely x = -x, and if the <u>resulting function is the same as the original</u>, then is even, if the <u>resulting function is the same as the original but negative</u>, is odd, if neither, well then neither :).
anyway, that said, let's first expand it and then plug in -x,
![\bf f(x)=(x^2-8)^2\implies f(x)=(x^2-8)(x^2-8)\implies f(x)=\stackrel{FOIL}{x^4-16x^2+64}\\\\[-0.35em]~\dotfill\\\\f(-x)=(-x)^4-16(-x)^2+64\qquad \begin{cases}(-x)(-x)(-x)(-x)=x^4\\(-x)(-x)=x^2\end{cases}\\\\\\f(-x)=x^4-16x^2+64\impliedby \stackrel{\textit{same as the original}}{Even}](https://tex.z-dn.net/?f=%20%5Cbf%20f%28x%29%3D%28x%5E2-8%29%5E2%5Cimplies%20f%28x%29%3D%28x%5E2-8%29%28x%5E2-8%29%5Cimplies%20f%28x%29%3D%5Cstackrel%7BFOIL%7D%7Bx%5E4-16x%5E2%2B64%7D%5C%5C%5C%5C%5B-0.35em%5D~%5Cdotfill%5C%5C%5C%5Cf%28-x%29%3D%28-x%29%5E4-16%28-x%29%5E2%2B64%5Cqquad%20%5Cbegin%7Bcases%7D%28-x%29%28-x%29%28-x%29%28-x%29%3Dx%5E4%5C%5C%28-x%29%28-x%29%3Dx%5E2%5Cend%7Bcases%7D%5C%5C%5C%5C%5C%5Cf%28-x%29%3Dx%5E4-16x%5E2%2B64%5Cimpliedby%20%5Cstackrel%7B%5Ctextit%7Bsame%20as%20the%20original%7D%7D%7BEven%7D%20)
Answer:
Suppose that A and B are points on the number line.
If AB=11 and A lies at 6, where could B be located?
If there is more than one location, separate them with commas
Step-by-step explanation:
Suppose that A and B are points on the number line.
If AB=11 and A lies at 6, where could B be located?
If there is more than one location, separate them with commas
Answer:
11ft is the width
Hope this helps! Please mark as brainliest.
Answer: 
Step-by-step explanation:
The missing figure is attached.
The perimeter of a rectangle is:

Where "l" is the lenght and "w" is the width.
You can identify in the figure that:

Then, knowing the perimeter of the rectangle, you can make the subsitution into the formula:

Now you must simplify and solve for "z"

Finally, substituting the value of "z" into
, you get:

Answer:
13x + 12
Step-by-step explanation:
The area of the walkway & garden - the area of the garden = the area of the walkway