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4 years ago

13

In accordance with 14 CFR Part 107, at what maximum altitude can you operate an sUAS when inspecting a tower with a top at 1,000

ft AGL at close proximity (within 100 feet)?

1 answer:

Svetllana [295]4 years ago

6 0

Answer:

The max altitude you can operate an sUAS on these given conditions is 1400ft AGL.

Step-by-step explanation:

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What is the x-intercept of the line that passes though the point (5, 3) with a slope of - 2/5?

lukranit [14]

Point/Slope Form of an equation!

(5,3)

slope of -2/5

x= 5
y = 3

y - y1 = m(x-x1)

y - 3 = -2/5(x-5)

y - 3 = -2/5x + 2

y = -2/5x + 5

x intercept of 5

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3 years ago

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3 years ago

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Help!! BRAINLIEST TOO!

natulia [17]

Answer:

36.5 inches

Step-by-step explanation:

Given

See attachment for the given data

Required

Which length is closest to 4.2lb

The given data is a linear dataset.

So, we start by calculating the slope (m)

$m =\frac{y_2 - y_1}{x_2 - x_1}$

Pick any two corresponding points from the table

So, we have:

$(x_1,y_1) = (8,1.21)$

$(x_2,y_2) = (12,1.63)$

So:

$m =\frac{y_2 - y_1}{x_2 - x_1}$

$m =\frac{1.63 - 1.21}{12 - 8}$

$m =\frac{0.42}{4}$

$m =0.105$

The linear equation is then calculated using:

$y = m(x - x_1) + y_1$

This gives:

$y = 0.105 * (x - 8) + 1.21$

Open bracket

$y = 0.105x - 0.84 + 1.21$

$y = 0.105x + 0.37$

To get the length closest to 4.2lb,

we set $y = 4.2$

Then solve for x

So, we have:

$y = 0.105x + 0.37$

$4.2 = 0.105x + 0.37$

Collect like terms

$0.105x= 4.2 - 0.37$

$0.105x= 3.83$

Solve for x

$x= 3.83/0.105$

$x\approx 36.5$

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3 years ago

Help numbers 3 pleaaaaaassssseeee

Varvara68 [4.7K]

It is 2 4/5, 2 4/5 is 2.8, 4/5 is greater than 3/4

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3 years ago

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If the parent function is y = 3x, which is the function of the graph? y = 0.5(3)x y = 2(3)x y = −2(3)x y = −0.5(3)x

german

Answer: If I remember correctly, the answer should be <em>y=-2(3)^x. </em>

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3 years ago