Answer:
The period when its more than halfway
= 2 < t ≤ 2.83 seconds ( to nearest hundredth).
Step-by-step explanation:
When is is halfway down the ramp d = 3920/2 = 1960 cm, so:
1960 = 490 t^2
t^2 = 1960/490 = 4
t = 2 seconds.
When it reaches the bottom d = 3920 :
t^2 = 3920/490 = 8
t = 2.83 seconds.
Answer:
ΔCFE is a right triangle
ΔBEC is an acute triangle
ΔBFG is an equilateral triangle
ΔGAF is an obtuse isosceles triangle
Answer:
84 c. –25 6. 119 7. –28 36 8a. 4 b. 52 LESSON EI.B: ANSWERS 709 Topic EI .... The length is 11 inches, and the width is 7 inches. ... 15x – 10 = 2x + 6 1 5 10. x = 1 11. y = 8x – 5 12. x = y + 8 8 49. .... 5xy 3 – 17x 2y + 8xy + 16x 3y – 7x 10. x 3y 2z – 10x 2y + 14x 2z + 3xy 2 – 25xz 2 LESSON ... 2 > y > –5 F a 4x 3 y 5 4y 3 x 22.
Step-by-step explanation:
D 85try telling me what like operation it would be so be easier to figure out
Answer:
14
Step-by-step explanation:
Sure thing, just use PEMDAS!
(Simplify first so that 24/4 = 6)
2 x 1 + 2 x 6
2 + 2 x 6
2 + 12
14
