2 years ago

Help me please, I’ll mark brainliest

1 answer:

8 0

I know that
20. 15
21. 18

Good luck though I remember doing it

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pochemuha

Answer:

V'(t) = $-250(1 - \frac{1}{40}t)$

If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.

Step-by-step explanation:

Given:

V = $5000(1 - \frac{1}{40}t )^2$ , where 0≤t≤40.

Here we have to find the derivative with respect to "t"

We have to use the chain rule to find the derivative.

V'(t) = $2(5000)(1 - \frac{1}{40} t)d/dt (1 - \frac{1}{40}t )$

V'(t) = $2(5000)(1 - \frac{1}{40} t)(-\frac{1}{40} )$

When we simplify the above, we get

V'(t) = $-250(1 - \frac{1}{40}t)$

If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.

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3 years ago

Tpy6a [65]

100 because you make ten groups of ten and it makes 100 Hope that helped Have a good day! :)

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2 years ago

garri49 [273]

same i love them they are too dangerous

plz mark me as brilliant answer

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IRISSAK [1]

Assuming the graduate was 18 when they graduated they would be 26.

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UkoKoshka [18]

Jenny gave away 142 super bouncy balls.

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