There would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers
Answer: There were 10 students in the class on the first day.
Step-by-step explanation:
Let x be the number of students of the first day.
Given: A college writing seminar increased its size by 50 percent from the first to the second day.
i.e. Number of students on second day = (Number of students on first day)+(50% of Number of students on first day)
= x +50% of x
= x+0.50x
= (1.50)x
=1.50x
Since, it is given that the total number of students in the seminar on the second day was 15.
i.e. 

Hence, there were 10 students in the class on the first day.
Answer:
Part a) The ratio of the perimeters is 
Part b) The ratio of the areas is 
Step-by-step explanation:
Part A) What is the value of the ratio (new to original) of the perimeters?
we know that
If two figures are similar, then the ratio of its perimeters is equal to the scale factor
Let
z-----> the scale factor
x-----> the perimeter of the new triangle
y-----> the perimeter of the original triangle

we have

substitute

Part B) What is the value of the ratio (new to original) of the areas?
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> the area of the new triangle
y-----> the area of the original triangle

we have

substitute


Answer:
V=343in³
Step-by-step explanation:
A=6a2
V=a
3V=6A3/2
36=6·2943/2
36=343in³
Answer:
The answer to your question is:
Step-by-step explanation:
m ∠ 1 = 27°
m ∠ 1 and m ∠ 2 are supplementary
m ∠ 1 + m ∠ 2 = 180°
27° + m ∠2 = 180°
m ∠ 2 = 180° - 27°
m = 2 = 153°