The 4C matrix is obtained when all elements of matrix C are multiplied by 4. It <span>has all the same elements as C, only multiplied by 4. Let's analyze all matrices A. Not all elements of A can be divided by 4 (3 can not be divided by 4, the solution is not a whole number). B. All elements of matrix B can be divided by 4, which means that B is a $C matrix (there is a matrix C which multiplied by 4 gives the matrix B). C. Not all elements of C can be divided by 4. D. Not all elements of D can be divided by 4.
You can take the a out of both values. There are no other factorable parts of this expression. Your factored version would look something like this- a(5a-4b) Hope that helped you out a bit nuzhat! ☺️
