The quotient of 6x^3+2x^2−x and x is 6x^3+2x^2−x divided by x
The value of the quotient 6x^3+2x^2−x by x is 6x^2 + 2x - 1
<h3>How to determine the quotient</h3>
The quotient expression is given as:
6x^3+2x^2−x divide by x
The above means that,
We divide 6x^2 by x, we divide 2x^2 by x and we divide -x by x.
So, we have:
6x^3+2x^2−x divide by x = 6x^2 + 2x - 1
Hence, the value of the quotient 6x^3+2x^2−x is 6x^2 + 2x - 1
Read more about quotient at:
brainly.com/question/7068223
Answer:
21p
Step-by-step explanation:
Answer:
18in cubed
Step-by-step explanation:
area times height equals volume. so,
13.5×1⅓=18.
so, the volume is 18in cubed.
The measure of angle D in the inscribed triangle is as follows;
∠D = 63 degrees
<h3>How to solve circle theorem?</h3>
The circle theorem can be use to find the ∠D as follows;
The triangle BCD is inscribed in the circle.
Using circle theorem,
The angle of each triangle is double the angle of the arc it create.
Therefore,
arc BC = m∠D
m∠B = 134 / 2 = 67 degrees.
Therefore, using sum of angles in a triangle.
67 + 50 + m∠D = 180
m∠D = 180 - 50 - 67
m∠D = 63 degrees.
learn more on circle theorem here: brainly.com/question/19906313
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