The following given problem can be expressed in the form
of:
E = 5.60 * T1 + 8.40 * T2
where,
E = total earning
T1 = normal hours worked
T2 = overtime hours
Assuming that the maximum T1 hours is 40 hours. Beyond
that is considered overtime, therefore:
287 = 5.60 * 40 + 8.40 * T2
T2 = 7.5 hours
<span>Therefore 7.50 overtime hours is needed.</span>
Answer:
5 times the quantity of 30 is (5*30) = 150 robots are needed.
Step-by-step explanation:
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Answer:
ano pong language ito?
Step-by-step explanation:
Step-by-step explanation:
I’m not entirely sure but maybe it’s c
5z>15-----subtract 2 on both sides
z>3----divide by 5
therefore, z must equal -10, or -4