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guapka [62]
3 years ago
15

On a map the scale is 1 inch = 125 miles. What is the actual distance between two cities if the map distance is 4 inches?

Mathematics
1 answer:
iragen [17]3 years ago
7 0
The distance between the two cities is 500 miles. Since each inch represents 125 miles, you multiply 4*125 to get 500 miles.
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Which is bigger 40% of 180 or 1/4 of 320
Veronika [31]
40% of 180 is 72
1/4 of 320 is 80

therefore 1/4 of 320 is bigger
3 0
3 years ago
Read 2 more answers
A survey of 1,168 tourists visiting Orlando was taken. Of those surveyed:
sesenic [268]

Answer:

624 tourists only visited the Magic Kindgom.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the tourists that visited LEGOLAND

-The set B represents the tourists that visited Universal Studios

-The set C represents the tourists that visited Magic Kingdown.

-The value d is the number of tourists that did not visit any of these parks, so: d = 74

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of tourists that only visited LEGOLAND, A \cap B is the number of tourists that visited both LEGOLAND and Universal Studies, A \cap C is the number of tourists that visited both LEGOLAND and the Magic Kingdom. and A \cap B \cap C is the number of students that visited all these parks.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,d,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

There were 1,168 tourists suveyed. This means that:

a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 1,168

We start finding the values from the intersection of three sets.

The problem states that:

16 tourists had visited all three theme parks. So:

A \cap B \cap C = 16

91 tourists had visited both LEGOLAND and Universal Studios. So:

(A \cap B) + (A \cap B \cap C) = 91

(A \cap B) = 91-16

(A \cap B) = 75

68 tourists had visited both the Magic Kingdom and Universal Studios. So

(B \cap C) + (A \cap B \cap C) = 68

(B \cap C) = 68-16

(B \cap C) = 52

87 tourists had visited both the Magic Kingdom and LEGOLAND

(A \cap C) + (A \cap B \cap C) = 87

(A \cap C) = 87-16

(A \cap C) = 71

295 tourists had visited Universal Studios

B = 295

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

295 = b + 52 + 75 + 16

b + 143 = 295

b = 152

266 tourists had visited LEGOLAND

A = 266

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

266 = a + 75 + 71 + 16

a + 162 = 266

a = 104

How many tourists only visited the Magic Kingdom (of these three)?

This is the value of c, the we can find in the following equation:

a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 1,168

104 + 152 + c + 74 + 75 + 71 + 52 + 16 = 1,168

c + 544 = 1,168

c = 624

624 tourists only visited the Magic Kindgom.

7 0
4 years ago
Find the distance between the points L(7,−1) and M(−2, 4).
kakasveta [241]

Answer:

The exact distance between the two points is 10

Step-by-step explanation:

8 0
4 years ago
Phyllis solved the compound inequality. She began by first breaking the inequality into two separate inequalities. Then she corr
umka21 [38]

Answer : option A

16<=2(3x-1) and 2(3x-1)<28

Phyllis solved the compound inequality. She began by first breaking the inequality into two separate inequalities. Then she correctly solved each for x

3<=x   and x<5

x>=3  and x<5

Now we graph the solution

x>=3, we have = sign so we use closed circle at 3.

Then for greater than symbol we shade to the right

For x<5, there is no = sign so we use open circle at 5

for < than symbol we shade to the left

For x>=3  and x<5, we take the intersection of both graphs

So option A is the answer.

8 0
3 years ago
Records of randomly selected births were obtained and categorized according to the day of the week (see below) that they occurre
Readme [11.4K]

Answer:

H0: Births occur with the same frequency on the different days of the week.

H1: At least one day has a different frequency of births than the other days.

Step-by-step explanation:

The null hypothesis is that births occur with equal frequency for each day of the week, as for the alternative which will be the opposite of the null, will e the claim that, the frequency for atleast one if not all of the weeks are different.

Hence,

H0 : p1 - p2 = 0

H1 : p1 - p2 ≥ 0

3 0
3 years ago
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