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3 years ago

SOMEBODY HELP ME IM DESPERATE

Mathematics

2 answers:

SOVA2 [1]3 years ago

7 0

Commutative property of multiplication
Your right

garik1379 [7]3 years ago

4 0

I believe it is the commutative property of multiplication. Commutative property is you can put the numbers in any order and it will have the same end result. I got multiplication because it is multiplication.

Hope this helps!

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Consider the universal set U and the sets X, Y, Z. U={1,2,3,4,5,6} X={1,4,5} Y={1,2} Z={2,3,5} What is (Z⋃X′)⋂Y?

beks73 [17]

X' = U - X

= {1,2,3,4,5,6} - {1,4,5}

= {2,3,6}

(ZUX') = {2,3,5} U {2,3,6}

= {2,3,5,6}

(Z⋃X′)⋂Y = {2,3,5,6} ⋂ {1,2}

= {2}

3 0

3 years ago

The value of a machine when new is £8000. The value depreciates by 10% each year. Work out its value after 3 years

Sladkaya [172]

5,600

8000*.10(y)
8000*.10(3)
8000*.3
5600

8 0

3 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

2 years ago

HELP i rlly need help bc its a test so reply fast

melomori [17]

Answer:

The answer is D.

Step-by-step explanation:

4 0

3 years ago

Please help me))))))))

Rus_ich [418]

For number 9 put the equation in the graphing calculator and see what the outcome is

5 0

3 years ago