Answer:
B. 
Step-by-step explanation:
Simplify the expression. Remember to go by the order of operations, or PEMDAS.
1) First, distribute the numbers outside of the set of parentheses to the terms inside the set of parentheses next to them. Then, simplify the fractions.
2) Finally, combine like terms. (This means to add or subtract constants and to add or subtract terms with the same variables.) You may need to convert terms to the same denominator in order to do so easier. Then, reduce the fraction.
Thus, the answer is .
The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.
In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.
So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:
Similarly,
Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:
1) 9m
2) 1/64
3) 50d^3
4) pq^2 (p-q) (p-q)
= pq^2 ( p^2 - 9p -9p +18)
= pq^4 - 18p^2q^2 + 8pq^2
= q^2 - 18p + 8
Answer:
c
Step-by-step explanation:
because 1 is also know as +1
Line 1 is in q1 and line 2 is q4
