Essentially when people ask you find the solution to system of equation, there asking at what x value do these to graphs intersect. The easiest way to do this is to get a graphing calculator, or desmos and type in the equation and find where they intersect. Heck, even the question says to solve it with a graph, but I'll demonstrate it algebraically.
One way you can do this is set the equation equal to each other. This is because you want to know at what x-value has the same y-value. So we get:
x^2 + 6x + 8 = x + 4
We can then combine like terms, or move everything to one side. So we get:
x^2 + 5x + 4 = 0.
Then we can use the quadratic formula to solve for x.
x=(-5 +/- sqrt(5^2 - 4(1)(4)))/(2(1)
This simplifies into:
(-5 +/- 3)/2
Finally we add and subtract:
(-5 + 3)/2 = x = -1
(-5 - 3)/2 = x = -4
And our solution is x = -1, x = -4
Answer:
x = 31/9 and y = 5/3
Step-by-step explanation:
It is given that,
3x - 2y = 7 -----(1)
3x + 4y = 17 ----(2)
<u>To find the solution by elimination method</u>
Step 1: Subtract eq(2) from eq(1)
3x - 2y = 7 -----(1)
<u> 3x + 4y = 17 </u>----(2)
0 - 6y = -10
6y = 10
y = 10/6 = 5/3
Step 2: Substitute the value of y in eq (1)
3x - 2y = 7 -----(1)
3x - 2*(5/3) = 7
3x = 7 + 10/3
3x = 31/3
x = 31/9
Therefore x = 31/9 and y = 5/3
The median of your data set will be 25.5
