Let width of the rectangular plot be x meters
then total of widths = 2x
and the length would be (550 - 2x) meters.
so the area = x(550 - 2x) = 550x - 2x^2
to find the maximum are find the derivative and equate to zero:-
f'(x) = 550 - 4x = 0
x = 550/4 = 137.5 meters = width
length = 550 - 2(137.5) = 275
Maximum area is when width = 137.5m and length = 275m
C because you have to do 50÷2=25 and 40÷2=20 and 20-25=5
4 divided by 3 = a whole and 3 repeated more than 4 times
(to use the number 4)
:D
It would be the square root of 3