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TEA [102]
3 years ago
5

What is the length of each side of the rectangle?​

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

AB =7  and CD = 7

BC =4 and AD =4

Step-by-step explanation:

A( 1,3)

B  (1,10)

C (5,10)

D (5,3)

As we can see in the graph, the AB = CD  and BC = AD

AB = the distance between the y points since the x values are the same

AB = 10-3 = 7

AB =7  and CD = 7

BC = the distance between the x points since the y values are the same

BC = 5-1 =4

BC =4 and AD =4

SVETLANKA909090 [29]3 years ago
3 0

Answer:

BC = AD = 4; AB = CD = 7  

Step-by-step explanation:

I have plotted your rectangle in the diagram below.

BC = x₂ - x₁

      = 5  -  1

      = 4

AD = BC

     = 4

AB =  y₂ - y₁

     = 10 -  3

     = 7

CD = AB

     = 7

BC = AD = 4; AB = CD = 7

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This parabola has<br> x-intercepts
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Answer:

see the explanation

Step-by-step explanation:

we have the quadratic equation

y=-16x^{2} +32x-10

This is a vertical parabola open downward

The vertex is a maximum

Find the x-intercepts of the quadratic equation

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

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Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16x^{2} +32x-10=0        

so

a=-16\\b=32\\c=-10

substitute in the formula

x=\frac{-32(+/-)\sqrt{32^{2}-4(-16)(-10)}} {2(-16)}

x=\frac{-32(+/-)\sqrt{384}} {-32}

x=\frac{-32(+/-)8\sqrt{6}}{-32}

x=\frac{-32(+)8\sqrt{6}}{-32}=\frac{32(-)8\sqrt{6}}{32}=0.39\ sec

x=\frac{-32(-)8\sqrt{6}}{-32}=\frac{32(+)8\sqrt{6}}{32}=1.61\ sec

therefore

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