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4 years ago

Will mark Brainliest [LOTS OF POINTS!] For JimThompson!

Mathematics

2 answers:

Komok [63]4 years ago

7 0

If you note that a square can be circumscribed by a circle (circumscribed is when the object is drawn in...right?) this makes things handy.

Draw a circle with the compass, for the diameter = side length of the square.
Drawing the circle ensures that the side lengths will all be congruent.

Now take your straightedge, and draw 4 sides, 2 sides parallel to each other on 2 outer sides of the circle, and 2 on the top, also parallel, BUT also perpendicular to the other 2 lines. You have a square

Katen [24]4 years ago

4 0

Answer:

If you note that a square can be circumscribed by a circl

Step-by-step explanation:

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Select all expressions that are equivalent to 64

pochemuha

Answer:

Step-by-step explanation:

What do you man what expressions or just expressions in general.

4 0

4 years ago

Sarah will ship packages for anyone. She charges $6 for her services and then $2.75 per item. How much would she charge to ship

Anastaziya [24]

The answer would be 70 6•8=48 2.75•8=22 and 48+22=70

8 0

2 years ago

Can someone please help me?<br> I have no idea what’s going on

Aleksandr-060686 [28]

Answer:

All triangle angles sum to 180

missing angle = 180 -92 -126 = 38

3x -37 = 38

3x = 75

x = 25

Step-by-step explanation:

4 0

4 years ago

The height of the right circular cylinder shown below is 10 feet and its base has a radius of 4 feet. A. B. C. D.

poizon [28]

Answer:

502.4ft^3

Step-by-step explanation:

Given data

Height= 10ft

radius= 4 ft

Hence the volume for the cylinder can be gotten as

v= πr^2h

v= 3.14*4^2*10

v=3.14*16*10

v=502.4ft^3

Therefore the volume of the cylinder is 502.4ft^3

7 0

3 years ago

F(t)=3-2t.2t+t write in standard form

VMariaS [17]

<h2>Hello!</h2>

The answer is: $f(t)=-4t^{2}+t+3$

Since we are given a quadratic function, we need to write it using the standard form of quadratic function (parabola).

The given function is:

$f(t)=3-2t.2t=+t$

<u>The standard form</u> of a parabola is:

$f(t)=a^{2}+bx+c$

Where,

a is equal to the quadratic variable coefficient

b is equal to the linear variable coefficient

c is the constant number

So, writing the function in the standard form will be:

$f(t)=3-2t*2t+t=3-4t^{2}+t=-4t^{2}+t+3$

$f(t)=-4t^{2}+t+3$

Where,

$a=-4\\b=1\\c=3$

Have a nice day!

7 0

3 years ago