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Paul [167]
3 years ago
5

Give the equation of the circle centered at the origin and passing through the point (0,3)

Mathematics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

The equation would be x^2 + y^2 = 9

Step-by-step explanation:

In order to find this, start with the base form of the circle.

(x - h)^2 + (y - k)^2 = r^2

Now we input the center as (h, k).

(x - 0)^2 + (y - 0)^2 = r^2

x^2 + y^2 = r^2

Now we can input the radius of 3 in for r

x^2 + y^2 = 3^2

x^2 + y^2 = 9

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Find the perimeter of the triangle whose vertices are the following specified points in the plane. (4,−7),(−10,−4) and (3,−7)
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Answer:

  √205 +√178 +1 ≈ 28.6595

Step-by-step explanation:

The distance formula tells you the distance between points (x1, y1) and (x2, y2) is ...

  d = √((x2 -x1)^2 +(y2-y1)^2)

Taken pairwise, the distances between the given points are ...

  d1 = √((-10-4)^2 +(-4-(-7))^2) = √(196+9) = √205

  d2 = √((3-(-10))^2 +(-7-(-4))^2) = √(169+9) = √178

  d3 = √((4-3)^2 +(-7-(-7))^2) = √1 = 1

Then the sum of the distances gives the perimeter:

  P = d1 +d2 +d3 = √205 +√178 +1 ≈ 28.6595

_____

In the attached figure, the distance "a" is the sum of the two long sides of the triangle.

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