Question

Solve for n: 4^n×2^-18=1​

Answer 1

One way to do it is by cleverly rewriting terms and using some basic algebraic identities:

$4^n\cdot 2^{-18}=1$.

$2^{2n-18}=2^0$.

$2n-18=0$.

$n=18/2=\boxed{9}$.

Another way would be to use logarithms, namely:

$4^n\cdot2^{-18}=1\implies n=\log_4\Big({\frac{1}{2^{-18}}}\Big)=\boxed{9}$.

Hope this helps.

Answer 2

Answer:

n = 9.

Step-by-step explanation:

4^n = 1 / 2^-18

4^n = 2^18

2^2n = 2^18

2n = 18

n = 9.