Problem 33
Use the distributive property on the side containing parentheses of each expression and compare it to the other side.
a) 3(5a + 3) = 15a + 9 not equal to 15a + 6
b) 2(7b - 2) = 14b - 4 not equal to 14b + 4
c) 5(2c + 3) = 10c + 15 not equal to 7c + 8
d) 3(d + 5/3) = 3d + 5 which is equal to 3d + 5
Answer for problem 33: d)
Problem 34
Use a proportion. Let the unknown number of bowls be x. The proportion is made up of two ratios that are set equal to each other. Set each ratio as a ratio of the number of avocados per bowls of guacamole. 3 avocados per 1 bowl (3/1) equals 17 avocados per x bowls (17/x).
Answer: 17/3 full bowls which is the same as 5 2/3 full bowls.
Answer:
Option A - Neither. Lines intersect but are not perpendicular. One Solution.
Option B - Lines are equivalent. Infinitely many solutions
Option C - Lines are perpendicular. Only one solution
Option D - Lines are parallel. No solution
Step-by-step explanation:
The slope equation is known as;
y = mx + c
Where m is slope and c is intercept.
Now, two lines are parallel if their slopes are equal.
Looking at the options;
Option D with y = 12x + 6 and y = 12x - 7 have the same slope of 12.
Thus,the lines are parrallel, no solution.
Two lines are perpendicular if the product of their slopes is -1. Option C is the one that falls into this category because -2/5 × 5/2 = - 1. Thus, lines here are perpendicular and have one solution.
Two lines are said to intersect but not perpendicular if they have different slopes but their products are not -1.
Option A falls into this category because - 9 ≠ 3/2 and their product is not -1.
Two lines are said to be equivalent with infinitely many solutions when their slopes and y-intercept are equal.
Option B falls into this category.
P-6 because you subtract the variable from the 6
Answer:
1680 ways
Step-by-step explanation:
Total number of integers = 10
Number of integers to be selected = 6
Second smallest integer must be 3. This means the smallest integer can be either 1 or 2. So, there are 2 ways to select the smallest integer and only 1 way to select the second smallest integer.
<u>2 ways</u> <u>1 way</u> <u> </u> <u> </u> <u> </u> <u> </u>
Each of the line represent the digit in the integer.
After selecting the two digits, we have 4 places which can be filled by 7 integers. Number of ways to select 4 digits from 7 will be 7P4 = 840
Therefore, the total number of ways to form 6 distinct integers according to the given criteria will be = 1 x 2 x 840 = 1680 ways
Therefore, there are 1680 ways to pick six distinct integers.
