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Harlamova29_29 [7]
3 years ago
8

What issue did the great compromise resolve

Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0

Answer:

The issue of the great compromise resolved representation.

Step-by-step explanation:

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Consider the following.x = t − 2 sin(t), y = 1 − 2 cos(t), 0 ≤ t ≤ 8πSet up an integral that represents the length of the curve.
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The length of the parametric curve (call it <em>C </em>) is given by

\displaystyle\int_C\mathrm ds=\int_0^{8\pi}\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt

We have

x=t-2\sin t\implies\dfrac{\mathrm dx}{\mathrm dt}=1-2\cos t

y=1-2\cos t\implies\dfrac{\mathrm dy}{\mathrm dt}=2\sin t

Now,

\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2=5-4\cos t

so that the arc length integral reduces to

\displaystyle\int_0^{8\pi}\sqrt{5-4\cos t}\,\mathrm dt

which has an approximate value of 53.4596.

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3 years ago
Let ​f(x)=x2+3x−10​. Enter the x-intercepts of the quadratic function in the boxes. x = and x =
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Answer:

X= 2.

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Step-by-step explanation:

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2 years ago
Can the sides of a triangle have lengths 1, 8, and 9?
Svetllana [295]

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Step-by-step explanation:

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2 years ago
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Answer:

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Step-by-step explanation:

|3x| = 12

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