Ask question

Ask question

All categories

3 years ago

6

If you were to create a histogram from the data shown in this stem-and-leaf plot, with each bar covering six values from 13 to 4

2, which bar would not have any data points?

1 answer:

Bingel [31]3 years ago

6 0

C) 25-30 I don’t really know why because I’m dumb but I added a screenshot for proof

You might be interested in

What is the equation in point slope form of a line that passes through the points (5,-3)

Illusion [34]

I think it's option 2 / b

4 0

4 years ago

Y=2x-5 -3x - 4y=-2

Whitepunk [10]

Answer:

y=-x/5 =3/5. that is how it is.

8 0

3 years ago

Using the formula of a cone, express r in terms of V,h, and pie

monitta

Answer:

the correct answer would be r= $\sqrt{x} \frac{3V}{h\pi }$

Step-by-step explanation:

hope this helps

plz mark brainliest

7 0

2 years ago

What are the solutions to the system?

artcher [175]

Answer:

A

Step-by-step explanation:

I just plugged each variable into the equation. A is the only one that works.

4 0

3 years ago

Find the slope-intercept form of the equation of the line passing through the given points.

Ugo [173]

$The\ slope-intercept\ form:y=mx+b\\\\The\ slope-point\ form:y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

$(1;\ 1)\to x_1=1;\ y_1=1\\\left(3;-\dfrac{1}{5}\right)\to x_2=3;\ y_2=-\dfrac{1}{5}.\\\\Subtitute:\\\\m=\dfrac{-\frac{1}{5}-1}{3-1}=\dfrac{-1\frac{1}{5}}{2}=-\dfrac{\frac{6}{5}}{2}=-\dfrac{\not6^3}{5}\cdot\dfrac{1}{\not2_1}=-\dfrac{3}{5}$

$y-1=-\dfrac{3}{5}\left(x-1\right)\\\\y-1=-\dfrac{3}{5}x+\dfrac{3}{5}\ \ \ \ |add\ 1\ to\ both\ sides\\\\\boxed{y=-\frac{3}{5}x+1\frac{3}{5}}$

5 0

4 years ago