Sample of gas occupies 10.0 L at 50 ˚C. Assuming that the pressure is constant what volume will
1 answer:
Answer:
<em>20 Liters</em>
Explanation:
If the pressure is supposed to be constant, one of Charles - Gay Lussac's laws can be used to solve the exercise. His statement says that "the volume of the gas is directly proportional to its temperature at constant pressure", mathematically it would be:
Considering T₁ = 50 ° C; V₁ = 10.0 L; and T₂ = 100 ° C, we can calculate the volume V₂ Clearing it from the equation and replacing the values to perform the calculation:
V2= (V1 x T2) / T1 = (10.0 L x 100°C) / 50 °C = 20 L
Therefore, <em>the gas at 100 ° C will occupy a volume of 20.0 L</em>.
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Solution : Given,
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Molar mass of sodium carbonate = 105.98 g/mole
Formula used for Molarity :
where,
w = mass of solute
M = Molar mass of solute
V = volume of solution in liter
Sodium carbonate is solute and water is solvent.
Now put the given values in above formula, we get the mass of solute in solution.
By rearranging the terms, we get
Therefore, the mass of solute in solution is .