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Artyom0805 [142]
3 years ago
10

Whats the name of the Changes in matter which require heat

Chemistry
1 answer:
Oksana_A [137]3 years ago
4 0

Answer:

Evaporation involves a liquid becoming a gas and sublimation is the change of a solid directly to a gas. Phase changes require either the addition of heat energy (melting, evaporation, and sublimation) or subtraction of heat energy (condensation and freezing).

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What is the volume occupied by 6.0 moles of carbon dioxide gas at standard conditions of temperature and pressure
aliina [53]

Answer: 134.4 L

Explanation:

it just is

3 0
3 years ago
Help ASAP!!! I need it now i have to write similar test tmrw
dusya [7]
A is Ea, which stands for activating energy. Energy is needed to get the reaction underway and Ea is the energy needed to “start” the reaction.

B is the temperature either released or absorbed.

The diagram shows that the reaction is exothermic based on the fact that the products energy is lower than the reactants. That is because energy (which is temperature in this case) is released during the process. If the reactants would have been lower than the products, the reaction would be endothermic.
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2 years ago
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Why is carbon dioxide nonpolar?
vovikov84 [41]
CO2<span> is a linear molecule and the Oxygen (O) atoms on each end are symmetrical. Polarity results from an unequal sharing of valence electrons. Because of this symmetry there is no region of unequal sharing and </span>CO2<span> is a</span>nonpolar<span> molecule</span>
8 0
3 years ago
What are the mole ratios of hydrazine
juin [17]

mole ratios of hydrazine should be 1:2. I could be wrong. Are there any options to choose from?

5 0
2 years ago
White vinegar is a 5.0% by mass solution of acetic acid in water. If the density of white
Alex_Xolod [135]

The pH = 2.41

<h3>Further explanation</h3>

Given

5.0% by mass solution of acetic acid

the density of white  vinegar is 1.007 g/cm3

Required

pH

Solution

Molarity of solution :

\tt M=\dfrac{\%mass\times \rho\times 10}{MW~acetic~acid}\\\\M=\dfrac{5\times 1.007\times 10}{60}\\\\M=0.839

Ka for acetic acid = 1.8 x 10⁻⁵

[H⁺] for weak acid :

\tt [H^+]=\sqrt{Ka.M}

Input the value :

\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.839}\\\\(H^+]=0.00388=3.88\times 10^{-3}\\\\pH=3-log~3.88=2.41

7 0
3 years ago
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