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denpristay [2]
4 years ago
9

a butcher has 10 3/4 pounds of ground beef that will be priced at $3.40 per pound. He divides the meat into 8 equal packages. To

the nearest cent, what will be the price of each package?
Mathematics
1 answer:
Delicious77 [7]4 years ago
8 0
I believe the price per package is $4.57, I think.
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P(x)=-2(x-9)^2+200P(x)=−2(x−9) ² + 200
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Answer:

224534

Step-by-step explanation:

because that croos the x axis

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DOES ANYONE USE THIS APP? <br>I NEED HELP​
Sergio039 [100]

Answer:

You can determine the root of the equation by multiple methods. However, that answer is correct. The root is -2.

Step-by-step explanation:

A root is where the graph crosses the x-axis. One trick I use to see if it is a root is by taking the numerator and plugging in the number for x. For example, \frac{x+2}{x^{2} -2}, and take the -2 and plug it in for x. The numerator would cancel out because -2 + 2 = 0. That is the way you can determine if it is a root or not.

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a book store is having a sale. all hardback books are 20% off l, and all paperbacks are 10% off. suppose you buy four paperbacks
Yuliya22 [10]
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</span>
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Differentiate from the first principle f(x)=1/(5x+3)​
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The proportions of blood phenotypes, A, B, AB, and O, in the population of all Caucasians in the United States are approximately
Vanyuwa [196]

Answer:

a. S = {A,B,AB,O}

b. P(A) = 0.41, P(B) = 0.1, P(AB) = 0.04, P(O) = 0.45

c. 0.45 = 45% probability that the person chosen at random has either type A or type AB blood

Step-by-step explanation:

a List the sample space for this experiment.

All possible blood types(A, B, AB or O). So

S = {A,B,AB,O}

b Make use of the information given above to assign probabilities to each of the simple events.

The proportions of blood phenotypes, A, B, AB, and O, in the population of all Caucasians in the United States are approximately .41, .10, .04, and .45, respectively.

So

P(A) = 0.41, P(B) = 0.1, P(AB) = 0.04, P(O) = 0.45

c What is the probability that the person chosen at random has either type A or type AB blood

P(A) + P(AB) = 0.41 + 0.04 = 0.45

0.45 = 45% probability that the person chosen at random has either type A or type AB blood

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