Answer:
B
Step-by-step explanation:
The recommended sample size n for point estimates is:
n = NX / (N + X - 1)
where N is the population size, and X is defined as:
X = Z² p (1 - p) / E²
where Z is the critical value, p is the sample proportion, and E is the margin of error.
Assume a confidence level of level of 95% and a margin of error of 5%.
α = 0.05, Z(α/2) = 1.96
E = 0.05
Of the 40 units tested, 2 had lifespans less than 26 days. So the proportion is:
p = 2/40 = 0.05
Therefore:
X = (1.96)² (0.05) (1 - 0.05) / (0.05)²
X = 73
Given N = 2000:
n = (2000) (73) / (2000 + 73 - 1)
n = 70.45
Rounding, the recommended sample size is 70.
100-75=25% did not like
25%=35 students how about 75%
75 x 35 divided by 25=105 students
105
On analyzing the question we can say that the angle ∠JKM of the triangle ΔJKL would be 42 as line MK bisects ∠JKL into ∠JKM & ∠MKL.
From the question it follows that line MK bisects angle ∠JKL into ∠JKM & ∠MKL where M is the point in the interior of ∠JKL.
Therefore, as we have given m∠JKL = 84 & m∠MKL = 42
and we have to find m∠JKM , we will simply write the equation as follow
m∠JKL = m∠JKM + m∠MKL
Inserting values we get,
84 = m∠JKM + 42
m∠JKM = 42
Hence, angle m∠JKM of the triangle ΔJKL is 42.
Learn more about questions related to triangles and their angles here
brainly.com/question/13273388
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Multiply the values then either divide by 2 or multiply by 2
