Answer:
The answer is "Slowing down
".
Explanation:
please find the complete question in the attached file.
In this question, if the block B weight were accounted for by kinetic the friction of frame A, because the blocks pushed at a consistent speed throughout the beginning.
Afterward, on block A, the resistance intensity rises, which allows frames to also be negative, which is defined in the graph, that's why the answer Slowing down is correct.
From gas equations
PV/T = Constant
Then
P1V1/T1 = P2V2/T2, but V1 = V2
Therefore,
P1/T1 = P2/T2
P2 = (P1T2)/T1
P1 = 40 psi
T1 = 60°F = 288.706 K
T2 = 90°F = 305.372 K
Substituting;
P2 = (40*305.372)/288.706 = 42.31 psi
Then, gauge pressure would read 42.31 psi.
Answer:
There's no PV graph. kindly provide it so we help