Answer:
A sloping surface separating air masses that differ in temperature and moisture content is called a front.
The mass of the man would remain the same…
His weight would change. Assuming the man’s weight on earth is 60N.
Since weight is a force, according to Newton’s second law, F = ma ( m = mass, a = acceleration due to gravity) First lets find the mass of the man, as it is required to find his weight on the moon.
F=ma[taking a of earth as10m/s
2
]
60=m.10[divide10onbothsides]
m=
10
60
= 6 Kg
Acceleration due to gravity on the moon is83%less than the acceleration due to gravity on earth(1.622m/s
2
).
F=ma
F=6.1.622=9.732 N
So a person weighting 60N on earth would approximately weight around 10Non the moon.
Answer:
The value of mass 1, m1= 6/5m
The value of mass 2, m2= 3/5m
Explanation:
case 1:
here tension and the acceleration will be:
for m1;
- mg-T=ma
- 2mg - 2T = 2ma .....1.
for m2:
adding the both equations,
2mg - 2T + 2T-mg = 2ma + ma/2
a = 2/5 g
putting the value of a into the equation 1.
mg - T = m* (2/5)g
T = 3/5 ( mg )
now
case 2:
The two identical blocks are released from the rest, the tension remains the same as the case 1.
so,
for m1:
for m2:
adding both equations we get,
2T-m2g + 2m2g - 2T = 0
m2 = m1 / 2
T = m1*g / 2
here we know that
T (case1) = T (case2)
3/5 ( mg ) = m1*g / 2
m1 = 6/5 m
hence
m2 = 3/5 m
learn more about tension here:
<u>brainly.com/question/23590078</u>
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