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Ghella [55]
3 years ago
8

An archer pulls her bowstring back 0.376 m by exerting a force that increases uniformly from zero to 251 N. (a) What is the equi

valent spring constant of the bow? N/m (b) How much work does the archer do on the string in drawing the bow? J
Physics
1 answer:
Amanda [17]3 years ago
8 0

Answer:

(A) 667.5 N/m

(B)

Explanation:

(A) Let the spring constant be k.

Using the formula F = kx

k = 251 / 0.376

K = 667.5 N/m

(B)

Work done

W = 0.5 × kx^2

W = 0.5 × 667.5 × 0.376 × 0.376

W = 47.2 J

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Two students are sitting 1.50 m apart. One student has a mass of 70.0 kg and
Galina-37 [17]

Answer:

1.08x10⁻⁷

Explanation:

F=(GM₁M₂)/r²

=((6.67x10⁻¹¹)(70)(52))/(1.5²)

=2.42788x10⁻⁷/2.25

=1.07905778x10⁻⁷

≈1.08x10⁻⁷

3 0
3 years ago
Cole is riding a sled with initial speed of 5 m/s from west to east. the frictional force of 50 n exists due west. the mass of t
stepan [7]
We can calculate the acceleration of Cole due to friction using Newton's second law of motion:
F=ma
where F=-50 N is the frictional force (with a negative sign, since the force acts against the direction of motion) and m=100 kg is the mass of Cole and the sled. By rearranging the equation, we find
a= \frac{F}{m}= \frac{-50 N}{100 kg}=-0.5 m/s^2

Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
a= \frac{v_f^2-v_i^2}{2d}
where
v_f=0 is the final speed of the sled
v_i=5 m/s is the initial speed
d is the distance covered

By rearranging the equation, we find d:
d= \frac{v_f^2-v_i^2}{2a}= \frac{-(5 m/s)^2}{2 \cdot (-0.5 m/s^2)}=25 m
3 0
3 years ago
A person skateboarding is part of a closed system that has 1,450 j of
soldier1979 [14.2K]

The gravitational potential energy of the system will decreases from 1,250 J to 625 J. Option A is corect.

<h3>What is the law of conservation of energy?</h3>

According to the Law of Conservation of Energy, energy can neither be created nor destroyed, but it can be transferred from one form to another.

The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.

TE=KE+GPE

Case 1;

1450 = 200 J+GPE

GPE=1450 -200

GPE=1250 J

Case 2;

1450 = 825 J+GPE

GPE=1450 -825

GPE=625 J

The gravitational potential energy of the system will decreases from 1,250 J to 625 J.

Hence, option A is corect.

To learn more about the law of conservation of energy, refer to brainly.com/question/2137260.

#SPJ1

6 0
2 years ago
Please someone write a book with me pls??
FromTheMoon [43]
What is it about, I can help.
3 0
3 years ago
Which type of galaxy is a spherical cluster of stars with extraordinary brightness and little dust and gas?
Elis [28]

Answer:

Elliptical galaxies

Explanation:

Edwin Hubble classified galaxies into three categories

Elliptical

Spiral

Lenticular

The elliptical galaxies have an elipsoidal shape roughly. They have stars which are old and the primary light source of the galaxy. The formation of new stars is very limited. This increases the brightness of the galaxy. The mass of the stars are low. So, far the percentage elliptical galaxies is low compared to other galaxies.

3 0
4 years ago
Read 2 more answers
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