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3 years ago

alicia got 60 questions correct on her science test. if she received a score of 75% how many questions were on the test?

Mathematics

1 answer:

Tomtit [17]3 years ago

6 0

If we know that she got 75%, we can write it as the fraction 75/100.
We also know that she got 60 correct out of an unknown number of questions, which we can call 'x'
We means we know that 75/100 = 60/x (the number of questions)
Cross multiply to get an equation.
75 * x=60 * 100 -----> 75x=6000
Divide both sides by 75 to solve for x.
6000/75=80
x=80, meaning that her test had 80 questions on it.

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a student claims that 8 to the third power times 8 to the -5 power is greater than 1 explain whether the student is correct or n

nika2105 [10]

I think he is not correct because there is negative number so it can't be greater than one

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3 years ago

If A = 8! and B = 8P8, then which one of the following is true:

meriva

Answer:

A. A = B

Step-by-step explanation:

Given

$A = 8!$

$B = ^8P_8$

Required

Which of the options is true

We start by simplifying $B = ^8P_8$

Permutation is calculated as follows

$^nP_r = \frac{n!}{(n - r)!}$

So.

$^8P_8 =\frac{8!}{(8 - 8)!}$

$^8P_8 =\frac{8!}{0!}$

0! = 1; So

$^8P_8 =\frac{8!}{1}$

$^8P_8 =8!$

Hence. B! = P!

<em>This implies that </em> $A = B = 8!$ <em />

4 0

3 years ago

AB is tangent to the circle k(O) at B, and AD is a secant, which goes through center O. Point O is between A and D∈k(O). Find m∠

drek231 [11]

Answer:

∠BAD=20°20'

∠ADB=34°90'

Step-by-step explanation:

AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.

Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus

∠BOD+∠BDO+∠DBO=180°

∠BDO+∠DBO=180°-110°20'=69°80'

∠BDO=∠DBO=34°90'

So ∠ADB=34°90'

Angles BOD and BOA are supplementary (add up to 180°), so

∠BOA=180°-110°20'=69°80'

In right triangle ABO,

∠ABO+∠BOA+∠OAB=180°

90°+69°80'+∠OAB=180°

∠OAB=180°-90°-69°80'

∠OAB=20°20'

So, ∠BAD=20°20'