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abruzzese [7]
3 years ago
10

What is the supplementally angle of 150.1

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

x =29.9

Step-by-step explanation:

Supplemental angles add to 180 degrees

x+150.1 = 180

Subtract 150.1 from each side

x+150.1 -150.1 = 180-150.1

x =29.9

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Choose any method to find the gcf of 40 16 and 24
Juli2301 [7.4K]

The GCF of 40 16 and 24 is 8

<h3>How to determine the GCF of 40 16 and 24?</h3>

The numbers are given as:

40 16 and 24

Start by listing out the factors of the numbers:

This is done as follows:

  • The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40
  • The factors of 16 are: 1, 2, 4, 8, 16
  • The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24

Then the greatest common factor in the above list is 8.

Hence, the GCF of 40 16 and 24 is 8

Read more about GCF at:

brainly.com/question/219464

#SPJ1

8 0
2 years ago
Find 6 rational numbers between -2/3 and 1/2?
a_sh-v [17]

Answer:

-3/6 -2/6 -1/6 0/6 1/6 2/6

4 0
3 years ago
Confused!! consider the polar axes with the points plotted below. Write the coordinates of point A in polar form. Be sure to wri
irinina [24]

Point A is on the 4th circle from the center, each circle has a radius of 1, so the 4th circle has a radius of 4. The point is also on the angle labeled 5PI/6.

The polar coordinate would be (4, 5PI/6)

Point C, you are given (-3,pi/3)

Because the radius is positive find the 3rd circle, which would be r = 3, Then find where PI/3 is on the circle and find the value opposite that which is 4pi/3

7 0
3 years ago
Another set of help? i need a hand lol
Zepler [3.9K]

Answer: C=14π≈43.98 ft

Step-by-step explanation:

To find the circumference of the circle, we use the equation C=2πr or C=πd. These 2 equations are equivalent because 2r is the same as d, diameter. In this case, we can use C=πd because the problems already gives us the diameter.

C=πd

C=14π≈43.98 ft

I hope this helps!

5 0
3 years ago
Please help I need it please please please
Fudgin [204]

Answer:

it is number 4 why because

7 0
2 years ago
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