An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equiva
lent toP (t) = A (one-half) Superscript StartFraction t Over 5,730 EndFraction
2 answers:
P(t) over A is equivalent to (one-half) Superscript t Over 5,730
<u>First Part:</u> D <em> P(t)/A=(1/2)^t/5,730</em>
<u />
<u>Second Part:</u> 0.8
<u />
<u>Third Part:</u> B <em>about 1,845 years</em>
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