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4 years ago

How do you do number 2? Help please and thank you.

Mathematics

1 answer:

Dmitrij [34]4 years ago

6 0

Answer:

{3,-1}

Step-by-step explanation:

m^2 -2m -3=0

What 2 numbers multiply to -3 and add to negative 2

-3* 1 = -3

-3 +1 =-2

(m-3) (m+1) =0

Using the zero product property

m-3 = 0 m+1 =0

m=3 m=-1

{3,-1}

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Segment AB measures 3 cm. Point O is the center of dilation. How long is the image of AB after a dilation with scale factor 1/5

avanturin [10]

Answer: a. AB = 15cm long.

b. AB = 11.1cm long.

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Image of AB after a dilation of scale factor 3.7 is 3cm × 3.7 = 11.1cm long.

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3 years ago

If the ratio of star shaped cookies to circular cookies is 5: 6 and the ratio of circular cookies to triangular cookies is 3: 10

SCORPION-xisa [38]

Answer:

$1:4$

Step-by-step explanation:

Without loss of generality, let there be 5 star shaped cookies. Following the proportions given, there will be 6 circular cookies. We can set up the following proportion to find out how many triangular cookies there would be:

$\frac{3}{10}=\frac{6}{x},\\3x=60,\\x=20$ .

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Simplifying this ratio we have $5:20 \implies \boxed{1:4}$ .

6 0

3 years ago

The difference of twice a number and 2 is less than -24.

tino4ka555 [31]

Answer:

x < -11

Step-by-step explanation:

Let x be the number

2x - 2 < -24
Add 2 to each side, so it now looks like this: 2x < -22
Divide each side by 2 to cancel out the 2 next to x. It should now look like this: x < -11

I hope this helps!

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3 years ago

What's the answer to this

KengaRu [80]

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3 years ago

Read 2 more answers

Data collected at Toronto Pearson International Airport suggest that an exponential distribution with mean value 2,725 hours is

Rzqust [24]

Answer:

$P(X >2)$

And we can calculate this with the complement rule like this:

$P(X>2) = 1-P(X$

And using the cdf we got:

$P(X>2) = 1- [1- e^{-\lambda x}] = e^{-\lambda x} = e^{-\frac{1}{2.725} *2}= 0.480$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}, x>0$

And 0 for other case. Let X the random variable of interest:

$X \sim Exp(\lambda=\frac{1}{2.725})$

Solution to the problem

We want to calculate this probability:

$P(X >2)$

And we can calculate this with the complement rule like this:

$P(X>2) = 1-P(X$

And using the cdf we got:

$P(X>2) = 1- [1- e^{-\lambda x}] = e^{-\lambda x} = e^{-\frac{1}{2.725} *2}= 0.480$

8 0

3 years ago