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Blababa [14]
4 years ago
10

Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $3,169 was collected on the sale of 1,325 ticket

s. How many of each type of ticket were sold?
Mathematics
1 answer:
eimsori [14]4 years ago
8 0

Answer:

461 adults and 864 students

Step-by-step explanation:

We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 1,325 tickets were purchased, then s+a=1325.

We also know that a total of $3,169 was collected and adult tickets cost $5 each and students cost $1 each. We can write 1s+5a=3169.

We will solve by substituting one equation into the other. We first solve the first equation for s which is s=1325-a. Substitute s=1325-a into 1s+5a=3169. Simplify and isolate the variable a.

1(1325-a)+5a=3169

1325-a+5a=3169

1325+4a=3169

1325-1325+4a=3169-1325

4a=1844

a=461

This means that 461 adults attended and 864 students attended since 864+461=1325.

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The first five terms of the sequence are; 4,600, 4,550, 4,500, 4,450, 4,400 and the total predicted number of sold cars for the first year is 51,900 cars

<h3>Arithmetic sequence</h3>

  • First month, a = 4,600 cars
  • Common difference, d = -50 cars

First five terms;

a = 4,600

a + d = 4600 + (-50)

= 4600 - 50

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cars predicted for the twelfth month.

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Total predicted number of sold cars for the first year:

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brainly.com/question/6561461

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