Question

Suppose the tree diagram below represents all the students in a highschool and that one of these students were chosen at random if the student is known to be a girl, what is the probabilty that the student is left-handed?
A. 1/6
B. 3/4
C.1/4
D.5/6

Answer 1

Answer:

Option A) $\frac{1}{6}$        

Step-by-step explanation:

We are given a tree diagram that represents all the students in a high school.

We have to find the probability that the student is left-handed provided if the student is known to be a girl.

Conditional Probability:

$P(B|A) = \displaystyle\frac{P(B \cap A)}{P(A)}$

Putting the values from the tree diagram:

$\text{P(Left handed student given the student is a girl)} = \displaystyle\frac{\text{P(Girl and Left handed)}}{\text{P(Girl)}}\\\\ = \frac{50}{300} = \frac{1}{6}$

Thus, 0.1667 is the probability that the student is left-handed provided if the student is known to be a girl.

Answer 2

Answer is A because 300 ÷6=50 so 50 student is left handed it's also same to 1/6.