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3 years ago

Answer this question please and thank you.

Mathematics

2 answers:

Mice21 [21]3 years ago

7 0

I think It’s 0.70 and in fraction is 512/729

Makovka662 [10]3 years ago

6 0

Answer: I think It’s 0.70 but if in fraction form 512/729 I can be wrong but I think I'm right

Step-by-step explanation:

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If the endpoints of AB are located at (0,7) and (8,8) what is the length of AB?

Leokris [45]

Answer:

√65

Step-by-step explanation:

The distance formula can be represented as

$\sqrt{(x_{2} -x_1)^2 + (y_2-y_1)^2}$

Taking (8,8) as (x₂, y₂) and (0,7) as (x₁, y₁), we have

$\sqrt{(8 -0)^2 + (8-7)^2}\\= \sqrt{8^2 + 1^2}\\= \sqrt{65}$

as our answer

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3 years ago

Yolanda spends 8 2⁄3 hours per month playing soccer. Approximately how many hours does she play soccer in a year? (There are twe

Anna11 [10]

The answer is: B

This problem will only need simple multiplication...

Answer = number of hours per months * months in a year

= 8 2/3 hours / month * 12 months
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3 years ago

The measurement of Angle N is 64°. Which angle measurement is complementary to Angle N?

Verizon [17]

Answer:

116°

Step-by-step explanation:

complementary angles add to 180 so

180-64= 116

5 0

3 years ago

Using the attached link below.

Serhud [2]

$\text{Use the Pythagorean theorem:}\\\\r-hypotenuse\\\\r^2=7^2+5^2\\\\r^2=49+25\\\\r^2=74\to r=\sqrt{74}$

$\sin=\dfrac{opposite}{hypotenuse}\\\\\cos=\dfrac{adjacent}{hypotenuse}\\\\\tan=\dfrac{opposite}{adjacent}\\\\\cot=\dfrac{adjacent}{opposite}\\\\\text{We have}\\\\for\ the\ angle\ y:\\\text{opposite = 7}\\\text{adjacent = 5}\\\text{hypotenuse = }\ \sqrt{74}\\\\for\ the\ angle\ x:\\\text{opposite = 5}\\\text{adjacent = 7}\\\text{hypotenuse = }\ \sqrt{74}$

$\csc x=\dfrac{1}{\sin x}\\\\\sec x=\dfrac{1}{\cos x}$

$A.\\\\\sin x=\dfrac{5}{\sqrt{74}}=\dfrac{5\sqrt{74}}{74}\\\\\csc y=\dfrac{1}{\frac{7}{\sqrt{74}}}=\dfrac{\sqrt{74}}{7}\\\\B.\\\\\tan x=\dfrac{5}{7}\\\\\cot y=\dfrc{5}{7}\\\\C.\\\\\cos x=\dfrac{7}{\sqrt{74}}=\dfrac{7\sqrt{74}}{7}\\\\\sec y=\dfrac{1}{\frac{5}{\sqrt{74}}}=\dfrac{\sqrt{74}}{5}$

$D.\\\sin\theta=\dfrac{2}{3}\\\\\sin^2\theta+\cos^2\theta=1\to\left(\dfrac{2}{3}\right)^2+\cos^2\theta=1\\\\\dfrac{4}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{4}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{5}{9}\to\cos\theta=\sqrt{\dfrac{5}{9}}\to\cos\theta=\dfrac{\sqrt5}{3}\\\\\tan\theta=\dfrac{\sin\theta}{\cos\theta}\to\tan\theta=\dfrac{\frac{2}{3}}{\frac{\sqrt5}{3}}=\dfrac{2}{3}\cdot\dfrac{3}{\sqrt5}=\dfrac{2}{\sqrt5}=\dfrac{3\sqrt5}{5}$

6 0

3 years ago

The width of the mirror in Shandon bathroom is 4/9 it's length. The area of the mirror is 576 square inches. What arelse the dim

In-s [12.5K]

The answer is 256 square inches

7 0

3 years ago