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Alex
3 years ago
10

Please help me understand how to do this

Mathematics
2 answers:
MrRa [10]3 years ago
6 0
Whenever you have something to the negative power, it will result in a fraction. So, if you have seven to the second power, it would be 49, and then you turn that into a fraction, which would be 1/49.
CaHeK987 [17]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Since the exponent 2 is negative, you will need to make it positive first. In order to do so, you can put 7^2 in the denominator. (If the original question was 1/7^-2 you could put 7^2 in the numerator to cancel out the negative). By doing this, the negative is removed and you are able to answer the question as 1/7^2 . The answer would then be D, since 7^2 is 49, but you put the number in the denominator because of the negative exponent.


I hope this makes sense!


(also: I am not exactly positive as to what standard form would be with just one number and an exponent, so I answered this as I have learned in my math classes.)

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Uhmmm B I pretty sure
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3 years ago
A box contains 12 balls of which 5 are red, and 7 are blue. If 4 balls are drawn from the box, in how many ways can this be done
mash [69]

Answer:

175 ways

Step-by-step explanation:

5 balls are red, and 7 balls  are blue making a total of 12 balls.

4 balls are drawn from the box,

1 ball is red and 3  balls are blue out of the 4 drawn from the box.

We have to choose 1 ball from 5 red balls and 3 blue balls from 7 blue balls.

Since the order is not essential we use combinations to find out

5C1 * 7C3= 5*35 = 175 ways

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3 years ago
A bag contains 6 white 2 black and 10 green marbles if a marble is selected at random find the probability that it is a white ma
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3 0
3 years ago
Read 2 more answers
The question is in the photo
masha68 [24]

Step-by-step explanation:

I think the answer is 3x square multiplied by 1

Coz anything raised to power 0 will always equal to 1

8 0
3 years ago
2x2 – 9x + 2 = –1
Reika [66]

Answer:

C)  The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0

\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}

\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}

\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}

2x^2-9x+2=-1

\implies 2x^2-9x+3=0

\implies a=2, b=-9, c=3

\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}

5 0
2 years ago
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