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3 years ago

Need help with this question what’s the correct answer for this

Mathematics

1 answer:

castortr0y [4]3 years ago

4 0

Answer:

these are similar triangles so ANGLES (FDE=BAC)

ANGLES

A+B+C=180

A+62+90=180

A=28

A=D=28

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Solve the inequality. m + 3 < 5 Please help with this

Klio2033 [76]

Answer:

Step-by-step explanation:

m+3 < 5

Isolate the m by subtracting 3

m+3 - 3 < 5 - 3

m < 2

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3 years ago

Find the slope using the formula. (3,-2) and (3, 6)

dangina [55]

Answer:

m = undef

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (3, -2)

Point (3, 6)

Step 2: Find slope m

Substitute: $m=\frac{6+2}{3-3}$
Add/Subtract: $m=\frac{8}{0}$
Divide: m = undef

When we divide anything by zero, we will get undefined. Therefore, this would be a vertical line.

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3 years ago

QUESTION 3 Construct a function for the relationship.

faltersainse [42]

Answer:

f(x)=3x-4

Step-by-step explanation:

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3 years ago

Maths 1. 24÷ (-6) 2. -15 ÷ 0.3 3. -4 ÷ (-20)

Lesechka [4]

Answer:

hope it helps

Step-by-step explanation:

1) -72

2) -50

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3 years ago

Read 2 more answers

A 200-liter tank initially full of water develops a leak at the bottom. Given that 20% of the water leaks out in the first 5 min

Leya [2.2K]

Answer:

127.53 liters left after 10 minutes

Step-by-step explanation:

Let

$A \to Amount$

$t \to time$

Given

$A(0) = 200$ --- initial

$A(5) = 200 * (1 - 20\%) = 160$ --- the amount left, after 5 minutes

Required

$A(10)$ --- amount left after 5 minutes

To do this, we make use of:

$A(t) = A(0) * e^{kt}$

$A(5) = 160$ implies that:

$160 = 200 * e^{k*5}$

Divide both sides by 200

$0.80 = e^{k*5}$

Take natural logarithm of both sides

$\ln(0.80) = \ln(e^{k*5})$

$\ln(0.80) = \ln(e^{5k})$

$\ln(0.80) = 5k\ln(e)$

So, we have:

$-0.223 = 5k$

Divide by 5

$k = -0.045$

So, the function is:

$A(t) = A(0) * e^{kt}$

$A(t) = 200 * e^{-0.045t}$

The amount after 10 minutes is:

$A(10) = 200 * e^{-0.045*10}$

$A(10) = 200 * e^{-0.45}$

$A(10) = 127.53$

3 0

3 years ago