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ryzh [129]
3 years ago
14

What is the slope of the line graphed on the coordinate plane?

Mathematics
2 answers:
77julia77 [94]3 years ago
6 0
The slope of a line running through points (-2,3) and (2,6) would be 3/4.

Nana76 [90]3 years ago
5 0
<h2>Answer</h2>

The slope of the line running through coordinates (-2, 3) and coordinates (2, 6) is \frac{3}{4}

<h2>Explanation</h2>

To get the slope of our line, we are going to use the slope formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

where

m is the slope of the line

(x_{1},y_{1}) are the coordinates of the first point on the line

(x_{2},y_{2}) are the coordinates of the second point

We know that our first point is (-2, 3), so  x_{1}=-2  and  y_{1}=3.  We also know that our second point is (2, 6), so  x_{2}=2  and  y_{2}=6.  Now let's replace the values in our slope formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{6-3}{2-(-2)}

m=\frac{3}{2+2}

m=\frac{3}{4}

We can conclude that the slope of our line is \frac{3}{4}.

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A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo
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Answer:

\frac{x^2}{61}-\frac{y^2}{37}  =1

Step-by-step explanation:

The standard equation of a hyperbola is given by:

\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

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\frac{x^2}{61}-\frac{y^2}{37}  =1

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