Answer:
11.94
Explanation:
Remark
Find the Potential Energy at the top.
Givens
m = 65 kg
h = 16.2 m
g = 9.81
PE = 65 * 9.81 * 16.2
PE = 10329.93
The tricky part is what do you do about Friction?
Formula
PE = Friction + KE
Solution
PE = 10329.93 Joules
Friction = 5700 Joules
Find the KE
10329.93 = 5700 + KE
KE = 10329.93 - 5700
KE = 4629.93
Find V from the KE formula
KE = 4629.93
m = 65
KE = 1/2 m v^2
KE = 1/2 65 v^2
4629.93 = 1/2 65 v^2
v^2 = 142.46
v = √142.46
v = 11.94
Answer:
Explanation: someone help me please you want free points right
Answer:
maximum possible temperature is 34.088°C
Explanation:
Given data
power output Q = 37 kW
volume flow rate = 11 x 10^-5 m3/s
temperature t = 14°C
to find out
maximum possible temperature T
solution
we can say
total water volume = 4 residents × volume flow
total water volume = 4 × 11 x 10^-5 = 44 × 10^-5 m³/s
so we say total water mass = 1000 × volume
total water mass = 1000 kg/m³ × 44 × 10^-5
total water mass = 0.44 kg
we know
dQ/dt = (dm/dt)× (S)× ( T - t)
so here we know specific heat of water S = 4.186 joule/gram °C
37 = 0.44 × 4.186 × (T-14)
T = 34.088°C
maximum possible temperature is 34.088°C
Answer:
B Eight light-minutes
Explanation:
In the case when the distance separated earth and the sun so here we orbit the sun for a 150 million km distance and the light moves would be 300,000 kilometers per second
Now divide this
= 150 million ÷ 300,000 kilometers per second
= 500 seconds
This 500 seconds represent 8 minutes and 20 seconds
Hence, option B is correct
Answer:
Explanation:
For Doppler effect in radar the formula is as follows
Δf = f₀ x 2v /c
Δf is change in frequency in reflected wave , f₀ is original frequency , v is velocity of source and c is velocity of right .
Δf = 2460 Hz , f₀ = 1.0525 x 10¹⁰ Hz , v = ? c is velocity of light .
2460 = 1.0525 x 10¹⁰ x 2 v / 3 x 10⁸
2460 = 105.25 x 2 v / 3
v = 2460 x 3 / (105.25 x 2 )
v = 35 .06 m /s .
(b)
Since the observed frequency is less , the source is moving away from the observer .
option (2) is correct .
