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Sophie [7]
3 years ago
5

A student exerts a force of 500 n pushing a box 10 m across the floor in 4 s. how much work does the student perform?

Physics
1 answer:
gregori [183]3 years ago
6 0
Work = Force * distance
W = Fd

Given F = 500 N, d = 10 m
W = (500)(10)
W = 5000 J

The work done is 500 Joules. The time of 4 s is irrelevant in this case.
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An object moves with a positive acceleration. Could the object be moving with increasing speed, decreasing speed or constant spe
Masja [62]

Answer:

Increasing speed.

Explanation:

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This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

In this scenario, an object moves with a positive acceleration. Thus, the object is moving with an increasing speed and as such it has acceleration in the same direction as its velocity with respect to time.

3 0
3 years ago
PLS HELP!!
stealth61 [152]

Answer:

B

Explanation:

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8 0
3 years ago
Read 2 more answers
In a mass spectrometer, a single-charged particle (charge e) has a speed of 1.0 × 10 6 m/s and enters a uniform magnetic field o
Nonamiya [84]

Answer:

The mass is  m  =6.4*10^{-28} \ kg

Explanation:

From the question we are told that

   The  speed of the charge is  v   = 1.0 *10^{6} \  m/s

    The  magnetic field is  B = 0.20 \ T

     The radius is r  =  0.02 \ m

      The value of the charge is  e  = 1.60 *10^{-19} \  C

The centripetal acting on the charge moving in the circular orbit is mathematically represented as

        F_c  =  \frac{mv^2}{r }

Now this centripetal force is due to the force exerted on the charge by the magnetic field on the charge which is mathematically represented as

     F_m  =  qv  B  sin\theta

At the maximum of this magnetic force \theta =  90 ^o

So  

     F_m  =  e v  B  sin(90)

      F_m  =  e v  B

Now given that it is this  magnetic force that is causing the circular motion we have that

       F_c  =  F_m

=>     \frac{mv^2}{r }  =  ev  B

=>     m  = \frac{e * B  *  r  }{v }

substituting values

       m  = \frac{ 1.60 *10^{-19} *  0.20   *  0.020   }{1.0*10^{6} }

     m  =6.4*10^{-28} \ kg

8 0
4 years ago
A car is idling at a stoplight. When the light turns green, the car takes 12 seconds to accelerate to 18.7 m/s. What is the aver
Sonbull [250]

Answer:

1.6 m/s^2

Explanation:

3 0
4 years ago
What is the mathematical expression for the electric ptential difference between points A and B when a charged particle is movin
ratelena [41]

Answer:

chang in V=\int\limits^B_A {E} \, ds

Explanation:

Since, as we know, the potential difference 'ΔV' is the difference of between the Potential energy per unit charge U/qo at one point 'B' to Potential energy per unit charge at other point 'A'. It so happens when a test charge 'qo' moves from point A to B, the potential difference becomes the change of potential energy of the system, i.e.

Potential Difference =\frac{change in U}{qo}=\int\limits^B_A {E} \, ds

4 0
3 years ago
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