Answer:
Explanation:
What happens to the total amount of kinetic energy is that as the train of coaster train loses height, they tend to speed up, this makes their potential energy to convert to kinetic energy due to the height, and as the motion continues, there is continuous gaining and losing of height by the object and its speed.
Each time there is a gain in height, there is also a corresponding conversion of kinetic energy to potential energy and while for each loss of height, there is also a corresponding conversion of potential energy to kinetic energy and this is as a result of speed.
This illustrates the relationship between work and energy.
An open system is a system that has external interactions.
a closed system is a physical system that does not allow certain types of transfers in our out of the system.
an isolated system obeys the conservation law that its total energy- mass stays constant.
Answer:
inductance per unit length is ![\frac{L}{l} = \frac{\mu_o}{2 \pi} ln (\frac{b}{a} )](https://tex.z-dn.net/?f=%5Cfrac%7BL%7D%7Bl%7D%20%3D%20%5Cfrac%7B%5Cmu_o%7D%7B2%20%5Cpi%7D%20ln%20%28%5Cfrac%7Bb%7D%7Ba%7D%20%29)
Explanation:
The diagram of coaxial cable is shown on the first uploaded image
From the question we are told that
The radius of the inner conductor is a
The current passing through the first cylindrical conductors is = I
The current passing through the first cylindrical conductors is = - I
The radius of the outer conductor is b
According to Ampere's law
∮ ![(\= B \ \= dl) = \mu_o I](https://tex.z-dn.net/?f=%28%5C%3D%20B%20%5C%20%5C%3D%20dl%29%20%3D%20%5Cmu_o%20%20I)
=> ![B (2 \pi r) = \mu_o I](https://tex.z-dn.net/?f=B%20%282%20%5Cpi%20r%29%20%3D%20%5Cmu_o%20I)
=>
The magnetic flux on the coaxial cable can be mathematically represented as
Now the emf induced in the coaxial cable is mathematically represented as
![\epsilon = \frac{d \phi }{dt} = L \frac{dI}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20%5Cfrac%7Bd%20%5Cphi%20%7D%7Bdt%7D%20%20%3D%20L%20%5Cfrac%7BdI%7D%7Bdt%7D)
=> ![\frac{d \phi }{dt} = L \frac{dI}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%20%5Cphi%20%7D%7Bdt%7D%20%20%3D%20L%20%5Cfrac%7BdI%7D%7Bdt%7D)
=> ![\int\limits {\phi} \, = L \int\limits {dI} \,](https://tex.z-dn.net/?f=%5Cint%5Climits%20%7B%5Cphi%7D%20%5C%2C%20%20%20%20%3D%20L%20%5Cint%5Climits%20%7BdI%7D%20%5C%2C)
=> ![\phi = L I](https://tex.z-dn.net/?f=%5Cphi%20%3D%20L%20I)
substituting for ![\phi](https://tex.z-dn.net/?f=%5Cphi)
![\frac{\mu_o I \ * \ l }{2 \pi r } ln [\frac{b}{a} ] = LI](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmu_o%20I%20%5C%20%2A%20%5C%20l%20%20%7D%7B2%20%5Cpi%20r%20%7D%20%20ln%20%5B%5Cfrac%7Bb%7D%7Ba%7D%20%5D%20%3D%20%20LI)
dividing through by ![l](https://tex.z-dn.net/?f=l)
![\frac{L}{l} = \frac{\mu_o}{2 \pi} ln (\frac{b}{a} )](https://tex.z-dn.net/?f=%5Cfrac%7BL%7D%7Bl%7D%20%3D%20%5Cfrac%7B%5Cmu_o%7D%7B2%20%5Cpi%7D%20ln%20%28%5Cfrac%7Bb%7D%7Ba%7D%20%29)
Answer:
the size, length, or amount of something, as established by measuring.
Explanation:
Answer:
21,000 kg(m/s)
Explanation:
1,400 times 15 is 21,000.