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4 years ago

Please help!

Physics

2 answers:

dmitriy555 [2]4 years ago

8 0

. a positive charge always moves from a higher potential to a lower potential is right answer.

ira [324]4 years ago

6 0

Answer: The correct answer is "a positive charge always moves from a higher potential to a lower potential".

Explanation:

Electric potential: It is defined as the work done in moving a unit positive charge from from reference point to a particular point.

The electric potential difference is defined as the electric potential between two points. In the circuit, battery provides the potential difference so that the electron can flow in the conductor easily. The negative terminal of the battery is at lower potential and the positive terminal of the battery is at higher potential.

The electron moves from lower potential to higher potential but the direction of the current is opposite to the direction of the electron.

A positive charge is moved from a higher potential to a lower potential but the negative charge moves from a lower potential to a lower potential.

In the given problem, a positive charge is moving from rest under the influence of an electric potential. Therefore, the correct option is (a).

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You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 690.0 kg and was tra

kirza4 [7]

Answer:

115 km/h

Explanation:

$m_1$ = Mass of car A = 690 kg

$m_2$ = Mass of car B = 520 kg

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration

u = Initial velocity

v = Final velocity

$a=\mu g\\\Rightarrow a=0.75\times 9.81\\\Rightarrow a=7.3575\ m/s^2$

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 7.3575\times 6+0^2}\\\Rightarrow v=9.396\ m/s$

$m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow u_1=\frac{(m_1 + m_2)v-m_2u_2}{m_1}\\\Rightarrow u_1=\frac{(690+520)9.396-520\times -\frac{74}{3.6}}{690}\\\Rightarrow u_1=31.96\ m/s$

Converting to km/h

$31.96\times 3.6=115.056\ km/h$

Initial velocity of car A = 115 km/h

7 0

3 years ago

Who sided with the French

Step2247 [10]

The French were helped by the Hurons

5 0

3 years ago

Read 2 more answers

Give an example of how energy from the sun gets into your cells

bulgar [2K]

We eat plants that use the energy from the sun to make food

6 0

3 years ago

Read 2 more answers

One way to cool a gas is to let it expand. When a certain gas under a pressure of 5.00 x 10^6 Pa at 25.°C is allowed to expand t

hichkok12 [17]

Answer:

The final temperature is T2= 5.35°C

Explanation:

Apply the Gay-lussacs's law we have

$\frac{P1}{T1} = \frac{P2}{T2}$

P1, initial pressure= 5.00 x 10^6 Pa

T1, initiation temperature= 25.°C

P2, final pressure= 1.07 x 10^6 Pa

T2, final temperature= ?

$\frac{5.00 * 10^6}{25} =\frac{1.07 *10^6}{T2} \\$

Cross multiplying and making T2 subject of formula we have

$T2 =\frac{1.07 *10^6*25}{5.00 * 10^6} \\\\T2= \frac{26.75}{5} \\T2= 5.35$

T2= 5.35°C

6 0

3 years ago

What are the magnitude and direction of the acceleration of an electron at a point where the electric field has magnitude 7400 N

bezimeni [28]

Answer: a = 1.32 * 10^18m/s² due north

Explanation: The magnitude of the force required to move the electron is given as

F = ma

The force exerted on the charge by the electric field of intensity (E) is given by

F = Eq

Thus

Eq = ma

a = E * q/ m

Where a = acceleration of charge

E = strength of electric field = 7400N/c

q = magnitude of electronic charge = 1.609 * 10^-6c

m = mass of an electronic charge = 9.109 * 10^-31kg

a = 7400 * 1.609 * 10^-16/ 9.109 * 10^-31

a = 11906.6 * 10^-16 / 9.019 * 10^-31

a = 1.19 * 10^-12 / 9.019 * 10^-31

a = 0.132 * 10^19

a = 1.32 * 10^18m/s²

As stated in the question, the direction of the electric field is due north hence, the direction of it force will also be north thus making the electron experience a force due north ( according to Newton second law of motion)

5 0

3 years ago