Answer:
lateral splaying of echoes in the far field can be improved by Increasing the maximum number of transmit focal zones and optimize their location.
B low frequency it is the lowest frequency
<u>Answer:</u>
Ball will move 92.8125 meter along the cliff in 7.5 seconds.
<u>Explanation:</u>
We have equation of motion ,
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In this case initial velocity = 0 m/s, acceleration = 3.3
, we need to calculate displacement when time = 7.5 seconds.
Substituting

So ball will move 92.8125 meter along the cliff in 7.5 seconds.
Wave speed = (wavelength) x (frequency)
Wavelength = (wave speed) / (frequency)
Wavelength = (9 m/s) / (0.5 Hz)
<em>Wavelength = 18 m</em>