Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
<h3>
Inscribing a square</h3>
The steps involved in inscribing a square in a circle include;
- A diameter of the circle is drawn.
- A perpendicular bisector of the diameter is drawn using the method described as the perpendicular of the line sector. Also known as the diameter of the circle.
- The resulting four points on the circle are the vertices of the inscribed square.
Alicia deductions were;
Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle
Benjamin's deductions;
The diameters must be perpendicular to each other. Then connect the points, in order, around the circle
Caleb's deduction;
No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.
It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.
Thus, Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
Learn more about an inscribed square here:
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Step-by-step explanation:
This is a probability related question, let the event be E
We know that the likelihood of an event happening is given as
Pr(E)=1
if an event will not occur the probability is
Pr(E)=0
a. This event is impossible: Pr(E)=0
b.This event will occur more often than not, but is not extremely likely:
Pr(E)=0<E>0.5
c.This event is extremely unlikely, but it will occur once in a while in a long sequence of trials:
Pr(E)=0<E<0.5
d.This event will occur for sure: Pr(E)=0
Answer: $25
Step-by-step explanation:
D. Aidan’s
The larger the sample size (number of people asked), the more accurate the results generally are, due to the law of large numbers.
Answer:
Find the complex solutions using the quadratic formula.
x
=
−
b
−
√
b
2
−
4
c
2
x
=
−
b
+
√
b
2
−
4
c
2
Step-by-step explanation:
